How do you solve for x in (3/4)x^2-12? I'm not sure how to factor this, unless there's another way to solve.
to "solve" you need an equation.
You don't have an equation.
Are you factoring (3/4)x^2-12 ?
if so, then
(3/4)x^2-12
= (3/4)(x^2 - 16)
= (3/4)(x-4)(x+4)