I am having a real issue with this one problem

the problem is : y=1/3x-3
I am supposed to graph the problem and then find the y intercept.

First I substituted x with 12.
Y=1/3(12)-3
s divided by 12 is 4, now I subtract 3from 4 and get 1
therefore, my first set reads(12,1)
I do the same operations for the second set, but this time I use 15, now I have my second set ( 15,2)

So mu ordered pairs are (12,1) and ( 15,2)

My y intercept is (0,-3)

Did I do this right or is my answers wrong?

correct, good job

Thanks again!

To graph the equation y = 1/3x - 3 and find the y-intercept, you followed the correct steps:

1. Substituting x = 12 into the equation: y = 1/3(12) - 3
Calculating: y = 4 - 3 = 1
So, the first set of coordinates is (12, 1).

2. Substituting x = 15 into the equation: y = 1/3(15) - 3
Calculating: y = 5 - 3 = 2
Thus, the second set of coordinates is (15, 2).

So, you obtained the correct ordered pairs: (12, 1) and (15, 2).

However, the y-intercept is not (0, -3).
To find the y-intercept, substitute x = 0 into the equation:

y = 1/3(0) - 3
Calculating: y = 0 - 3 = -3

The y-intercept is (0, -3), and you are correct.