Show a balanced equation for a diprotic acid reacting with a tribasic base.
I have an example of a diprotic acid as H2SO4 and a triprotic base as H3PO4. can i use those? if so please help balance.
sorry correction tribasic base is K3PO4
Yes, you can use H2SO4 as a diprotic acid and H3PO4 as a tribasic base. To balance the equation, you need to consider the number of hydrogen (H) atoms, oxygen (O) atoms, and sulfur (S) atoms on both sides of the equation.
The balanced equation for the reaction between H2SO4 and H3PO4 is as follows:
1. Start by writing down the reactants: H2SO4 + H3PO4
Next, let's balance the sulfur (S) atoms. There is only one sulfur atom on the left side, so we need to include one on the right side:
H2SO4 + H3PO4 → H2SO4 + H3PO4
Now, let's balance the phosphorus (P) atoms. There is only one phosphorus atom on the right side, so we also need to include one on the left side:
H2SO4 + H3PO4 → H2SO4 + H3PO4
Finally, let's balance the hydrogen (H) and oxygen (O) atoms. The diprotic acid, H2SO4, has two hydrogen atoms and four oxygen atoms. The tribasic base, H3PO4, has three hydrogen atoms and four oxygen atoms. To balance these, we can multiply the tribasic base by two:
H2SO4 + 2H3PO4 → H2SO4 + H6PO4
Now, we have the balanced equation for the reaction between H2SO4 and H3PO4:
H2SO4 + 2H3PO4 → H2SO4 + H6PO4