Some children were seated around a large round table. They pass around a box of candy containing 25 pieces. Bob took the first piece. Each child takes a piece of candy as the box is passed around. Bob also gets the last piece, and he may have more than the first and last piece.
How many children could be seated around the table.
Now, I really don't get this...and I need some help to start....but I think there mightbe 18 children other than Bob....thats just a guess.
There is no good answer with the information you've given us. Since Bob got the first and last piece, then there must be a total of 24 children around the table. However, the directions stating that he "may have more than the first and last piece" could mean that there could be as few as three children.
I KNOW!
How many whole numbers are there between 99 and 1000?
Dylan has earned $115 mowing lawns. This is 46% of what he needs to the bike he wants.
To find the number of children that could be seated around the table, we need to consider how the candy is being passed around.
Let's start by visualizing the passing of the candy around the table. Since Bob takes the first piece and the last piece, we can think of the candy as passing through a loop where each child takes one piece before it reaches Bob again.
Since Bob takes the first and last piece, we know that there must be at least two children in order for the candy to have a chance to reach Bob again. Let's assume there are only two children for now and see if it satisfies the given conditions.
If there are only two children, the candy would go from Bob to the other child, and then back to Bob. This means that the candy has taken one complete loop around the table. It doesn't matter how many pieces of candy are in the box initially since Bob will always take the last piece, so this scenario is possible.
Now, let's check if there can be more than two children. If there are more than two children, the candy would go from Bob to the first child, then to the second child, and so on. This means that the candy would need to make a complete loop around the table before reaching Bob again.
Since Bob takes the last piece of candy, we know that the total number of children must be a divisor of 25 (the number of pieces in the box) plus one (for Bob since he doesn't count when determining the number of children). This is because for the candy to complete a full loop and reach Bob, the total number of children multiplied by the number of candies each child takes must be equal to 25 plus 1.
To find the number of divisors of 26, we can factorize it. The prime factorization of 26 is 2 * 13. So, the divisors of 26 are 1, 2, 13, and 26.
However, we need to exclude Bob from this count. So, the possible numbers of children that could be seated around the table are 1, 2, 13, and 26 - 1 (since Bob is not counted as a child).
Therefore, there can be three possible numbers of children seated around the table: 1, 2, or 12.
In conclusion, there can be 1, 2, or 12 children seated around the table, in addition to Bob.