im trying to rearrange the following equation for x but getting confused because of the brackets and squares. I understand the process of changing the subject but on more simple equations. Please can you help me. Here's the equation

y = 3(x+5)^2

divide by three.

y/3=(x+5)^2
take the square root of each side.

+-sqrt(y/3)=x+5
solve for x. check both roots.

Of course, I can help you with that! To rearrange the equation y = 3(x+5)^2 for x, we need to follow a step-by-step process. Let's break it down:

Step 1: Expand the square
Apply the exponent of 2 to the expression inside the brackets:
y = 3(x^2 + 10x + 25)

Step 2: Distribute the 3
Multiply each term inside the brackets by 3:
y = 3x^2 + 30x + 75

Step 3: Move the other terms away from x
To isolate the x terms, we need to move the constant term (75 in this case) away from the x terms. We can do this by subtracting it from both sides of the equation:
y - 75 = 3x^2 + 30x

Step 4: Divide by the coefficient of x^2
Divide both sides of the equation by 3, which is the coefficient of x^2:
(y - 75)/3 = x^2 + 10x

Step 5: Set the equation equal to zero
To further manipulate the equation, let's set it equal to zero by subtracting (y - 75)/3 from both sides:
0 = x^2 + 10x - (y - 75)/3

And there you have it! The rearranged equation for x is:
x^2 + 10x - (y - 75)/3 = 0

Please keep in mind that this is just one possible way to rearrange the equation. Depending on the context or specific requirements, further simplifications may be possible.