1) The vector sum of three vectors gives a resultant equal to zero. what can you say about the vectors?

2) Vector is 3.00 units in length and points along the positive x-axis. Vector is 4.00 units in length and points along the negative y-axis.Use graphical methods to find the magnitude and direction of the following vectors:
A) A+B
B) A-B
C) A+2B
D) B-A

1) They are in an equilibrant system.

2)That has to be done on graph paper.

well first they are in equilibrium

second using Pythagoras Theorem you get 5 as the magnitude

using tan^-1 Vy/Vx you'll get 53.1 as the degree

1) If the vector sum of three vectors gives a resultant equal to zero, it means that the vectors are in a state of equilibrium. This implies that the vectors must have opposite directions and equal magnitudes, such that their sum cancels out to zero.

2) A) To find the magnitude and direction of A + B, we can use graphical methods. We start by drawing vector A along the positive x-axis, which has a length of 3.00 units. Then, we draw vector B along the negative y-axis, which has a length of 4.00 units. To find the resultant vector A + B, we place the tail of vector B at the head of vector A. The magnitude of the resultant vector is given by the diagonal connecting the tail of A to the head of B, which can be calculated using the Pythagorean theorem. In this case, the magnitude is sqrt((3.00^2) + (4.00^2)) = 5.00 units. The direction of the resultant vector can be found using trigonometry, specifically the tangent function. The angle between the resultant vector and the positive x-axis can be calculated as arctan(4.00/3.00) = 53.13 degrees.

B) To find the magnitude and direction of A - B, we follow the same steps as above, but now we subtract vector B from vector A. This means we place the tail of vector B at the head of vector A and draw the resultant vector from the tail of A to the head of B. The magnitude of the resultant vector is still 5.00 units. However, the direction is now in the opposite direction of the previous case. So, it is -53.13 degrees with respect to the positive x-axis.

C) To find the magnitude and direction of A + 2B, we first calculate the individual vectors A and 2B. As mentioned in the previous steps, A has a magnitude of 3.00 units and points along the positive x-axis. Vector 2B can be obtained by multiplying the magnitude of B (4.00 units) by 2, which gives 8.00 units. The direction of 2B remains the same as B. Next, we add A and 2B like in step A, by placing the tail of 2B at the head of A. The magnitude of the resultant vector is sqrt((3.00^2) + (8.00^2)) = 8.60 units. The direction of the resultant vector can be found using trigonometry, which is arctan(8.00/3.00) = 70.53 degrees with respect to the positive x-axis.

D) To find the magnitude and direction of B - A, we subtract vector A from vector B. This means we place the tail of vector A at the head of vector B and draw the resultant vector from the tail of B to the head of A. The magnitude of the resultant vector is still 8.60 units. The direction, however, is now in the opposite direction of the previous case when subtracting B from A. So, it is -70.53 degrees with respect to the positive x-axis.

1) If the vector sum of three vectors gives a resultant equal to zero, it means that the three vectors are balanced or cancel each other out. This implies that the vectors must have equal magnitudes and opposite directions.

2) To find the magnitude and direction of the given vectors using graphical methods:

A) A + B:
Start at the tail of vector A and draw vector B. The sum of the two vectors will be the vector from the tail of A to the head of B. Measure the length of this resultant vector using a ruler. This will give you the magnitude. To find the direction, draw a line from the tail of A to the head of B and measure the angle it makes with the positive x-axis using a protractor.

B) A - B:
Start at the tail of vector A and draw vector B in the opposite direction. The difference between the two vectors will be the vector from the tail of A to the head of B. Measure the length of this resultant vector using a ruler for magnitude. To find the direction, draw a line from the tail of A to the head of B and measure the angle it makes with the positive x-axis using a protractor.

C) A + 2B:
Start at the tail of vector A and draw twice the length of vector B in the same direction as vector B. The sum of these two vectors will be the vector from the tail of A to the head of the doubled B vector. Measure the length of this resultant vector using a ruler for magnitude. To find the direction, draw a line from the tail of A to the head of the doubled B vector and measure the angle it makes with the positive x-axis using a protractor.

D) B - A:
Start at the tail of vector B and draw vector A in the opposite direction. The difference between the two vectors will be the vector from the tail of B to the head of A. Measure the length of this resultant vector using a ruler for magnitude. To find the direction, draw a line from the tail of B to the head of A and measure the angle it makes with the positive x-axis using a protractor.