suppose you heat a hydrate too quickly and some of it was lost as it spattered out of the container. Explain how this would affect the calculated percent of mass and the chmical formula

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asked by sara
  1. Loss of some of the sample due to spattering will result in a larger weight loss and that is translated to a larger amount of water. Therefore, the percent water will be too high. If the formula of a hydrate is written as AB.xH2O, then x will be larger than it should be.

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