If you are given a 0.32 g piece of sodium metal to react with water, how many moles of HCl would it take to neutralize the sodium hydroxide produced?
2Na + 2H2O ==> H2 + 2NaOH
HCl + NaOH ==> NaCl + H2O
0.32 g Na x (1 mole/23 g Na) = ?? moles Na.
You know from the equation that 2 moles Na will produce 2 moles NaOH (of course 1 mole produces 1 mole) and you know 1 mole HCl reacts with 1 mole NaOH. Therefore, the moles of Na will be the same as the moles of HCl required.
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Well, I wouldn't want to test your sense of humor, but I'll try to provide a quirky response!
Ah, the wonders of chemistry! So, if you have 0.32 grams of sodium metal reacting with water to produce sodium hydroxide, you need to figure out how much sodium hydroxide is formed.
To do that, you'll first need to convert the mass of sodium metal to moles. Since the molar mass of sodium is 22.99 g/mol, you can calculate the number of moles of sodium.
Then, in the balanced chemical equation for the reaction, you can see that one mole of sodium metal reacts with one mole of water to produce one mole of sodium hydroxide. So, the number of moles of sodium hydroxide formed will be the same as the number of moles of sodium.
Now, since you want to neutralize the sodium hydroxide with HCl, you'll need an equal number of moles of HCl.
So, all you need to do is calculate the number of moles of sodium from the given mass, and that would be the same number of moles of HCl needed to neutralize the sodium hydroxide.
Now, I admit, this might not be the kind of answer you were hoping for, but I hope it still brings a smile to your face!
To determine how many moles of HCl would be needed to neutralize the sodium hydroxide produced, we need to first find the number of moles of sodium present in the 0.32 g piece of sodium metal.
The molar mass of sodium (Na) is approximately 22.99 g/mol.
Using the formula:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles of sodium = 0.32 g / 22.99 g/mol
Now that we know the number of moles of sodium, we can determine the number of moles of sodium hydroxide (NaOH) produced in the reaction. The balanced equation for the reaction between sodium and water is:
2Na + 2H₂O -> 2NaOH + H₂
This means that for every 2 moles of sodium reacted, 2 moles of sodium hydroxide are produced. Therefore, the number of moles of NaOH produced is equal to the number of moles of sodium.
Number of moles of sodium hydroxide = Number of moles of sodium
Now, we can calculate the number of moles of HCl needed to neutralize the sodium hydroxide produced. The balanced equation for the reaction between HCl and NaOH is:
HCl + NaOH -> NaCl + H₂O
This means that for every mole of sodium hydroxide, one mole of hydrochloric acid is needed to neutralize it.
Number of moles of HCl = Number of moles of sodium hydroxide = Number of moles of sodium
Therefore, the number of moles of HCl required to neutralize the sodium hydroxide produced is equal to the number of moles of sodium, which we calculated earlier.
To find the number of moles of HCl required to neutralize the sodium hydroxide produced, we first need to calculate the number of moles of sodium hydroxide formed.
The balanced chemical equation for the reaction of sodium with water is:
2Na + 2H2O -> 2NaOH + H2
From the equation, we can see that 2 moles of sodium react to produce 2 moles of sodium hydroxide. Therefore, the number of moles of sodium hydroxide produced can be calculated using the given mass of sodium.
Step 1: Convert the mass of sodium to moles.
Given mass of sodium = 0.32 g
Molar mass of sodium (Na) = 22.99 g/mol
Number of moles of sodium = Mass of sodium / Molar mass of sodium
= 0.32 g / 22.99 g/mol
Step 2: Calculate the number of moles of sodium hydroxide produced.
Since the balanced equation shows that 2 moles of sodium react to produce 2 moles of sodium hydroxide, the number of moles of sodium hydroxide formed will be the same as the number of moles of sodium.
Therefore, the number of moles of sodium hydroxide formed = 0.32 g / 22.99 g/mol
Step 3: Determine the number of moles of HCl required.
From the balanced equation, we can see that 2 moles of sodium hydroxide react with 1 mole of HCl to form 2 moles of NaCl (table salt) and 2 moles of water.
So, the number of moles of HCl required will be half (1/2) the number of moles of sodium hydroxide formed.
Therefore, the number of moles of HCl required = (0.32 g / 22.99 g/mol) / 2
Now, you can perform the calculations to find the exact number of moles of HCl required using the given values.