TO WAT VOLUME SHOULD YOU DILUTE 130ML OF AN 8.40 M CUCL2 SOLUTION SO THAT 65.0ML OF THE DILUTED SOLUTION CONTAINS 5.9 G CUCL2?
To calculate the volume of the diluting solution, we can use the equation:
C1V1 = C2V2
where:
C1 = initial concentration of the solution (8.40 M)
V1 = initial volume of the solution (130 mL)
C2 = final concentration of the solution (unknown)
V2 = final volume of the solution (65 mL)
First, let's calculate the final concentration (C2) using the given mass of CuCl2 and the final volume of the solution.
1. Calculate the moles of CuCl2:
moles = mass / molar mass
moles = 5.9 g / (63.55 g/mol + 2 * 35.45 g/mol)
moles = 5.9 g / 134.45 g/mol
2. Calculate the final concentration (C2):
C2 = moles / V2
C2 = (5.9 g / 134.45 g/mol) / 0.065 L
C2 = 5.9 g / (134.45 g/mol * 0.065 L)
C2 ≈ 0.8514 M
Now, we can calculate the volume of the diluting solution (V2):
C1V1 = C2V2
V2 = (C1V1) / C2
V2 = (8.40 M * 0.130 L) / 0.8514 M
V2 ≈ 1.282 L
Therefore, you would need to dilute the 130 mL of the 8.40 M CuCl2 solution to a volume of approximately 1.282 L to obtain a 65.0 mL solution with a concentration of 0.8514 M.
To determine the volume to which you should dilute the 130 mL of an 8.40 M CuCl2 solution, we can use the formula for dilution:
M1V1 = M2V2
Where:
M1 = Initial concentration of the solution before dilution
V1 = Initial volume of the solution before dilution
M2 = Final concentration of the diluted solution
V2 = Final volume of the diluted solution
In this case, we are given:
M1 = 8.4 M
V1 = 130 mL
M2 = unknown
V2 = 65 mL
We are also given the amount of CuCl2 in the diluted solution, which is 5.9 g.
First, we need to calculate the number of moles of CuCl2 in the diluted solution using the given mass and molar mass.
Number of moles (n) = mass / molar mass
n = 5.9 g / (63.55 g/mol + 2 x 35.45 g/mol) ≈ 0.0519 mol
Next, we will substitute the given and calculated values into the dilution formula:
(M1)(V1) = (M2)(V2)
(8.4 M)(130 mL) = (M2)(65 mL)
Simplify the equation:
8.4 M * 130 mL = M2 * 65 mL
1092 = 65M2
M2 = 1092 / 65 ≈ 16.8 M
So, the final concentration of the diluted solution (M2) is approximately 16.8 M.
To find the volume to which you should dilute the 130 mL of the initial solution, take the equation:
(M1)(V1) = (M2)(V2)
Rearrange the equation to solve for V1:
V1 = (M2 * V2) / M1
Substitute the given values:
V1 = (16.8 M * 65 mL) / 8.4 M
V1 = 131 mL
Therefore, to dilute 130 mL of an 8.40 M CuCl2 solution so that 65.0 mL of the diluted solution contains 5.9 g of CuCl2, you would need to add 131 mL of solvent (often water) to the initial solution.