Lisa needs to make 2 times as many tuna as cheese sandwiches and 4 times as many ham as cheese sandwiches. If Lisa makes 56 sandwiches, how many of each of the 3 kinds will she make?
8 cheese sandwiches
16 tuna sandwiches
32 ham sandwiches
T=2C
H=4C
T+H+C=56
2c+4C+c=56
cheese= 8
go from there.
2c + 4c +c = 56
C=8
Tuna=16
Ham =32
To solve this problem, let's represent the number of cheese sandwiches as "x".
Since Lisa needs to make 2 times as many tuna sandwiches as cheese sandwiches, she will make 2x tuna sandwiches.
Similarly, she will make 4 times as many ham sandwiches as cheese sandwiches, which gives us 4x ham sandwiches.
According to the problem statement, Lisa makes a total of 56 sandwiches. Therefore, we can set up the following equation:
x + 2x + 4x = 56
Combining like terms, this equation simplifies to:
7x = 56
To isolate x, divide both sides of the equation by 7:
x = 56 ÷ 7 = 8
Now that you know the value of x, substitute it back into the equations we established earlier to find the values of the other three sandwich types.
The number of cheese sandwiches is x, which is 8.
The number of tuna sandwiches is 2x, which is 2(8) = 16.
The number of ham sandwiches is 4x, which is 4(8) = 32.
So, Lisa will make 8 cheese sandwiches, 16 tuna sandwiches, and 32 ham sandwiches.