A 10cm times 10cm times 10cm wood block with a density of 700kg/m^{3} floats in water. What is the distance from the top of the block to the water if the water is fresh?
weight= density*volume*g
weight=700*(0.001)*9.81
weight=6.86newton
weight=densitywater*g*10cm*10cm*depth
6.86=1000*9.81*.1*.1*d
6.86=98.1*d
d=.0699...which is wrong
i have to get an answer in cm.
I bet it wants the distance in cm... 6.99 or rounded to 7 cm.
Works looks right
its asking for the water level from the top. so just subtract 7 from 10 and we get 3cm!
THANKS TO The anonomyous person who cleared this question up its been bothering me for days!!!
thanks....u really helped a lot...people have to specify when helping out someone
To find the correct answer in cm, you need to convert the density of water into the same units as the density of the wood block. The density of water is 1000 kg/m³, but you need it in kg/cm³ in order to use the same units as the wood block's density.
To convert the density of water from kg/m³ to kg/cm³, divide it by 1000 because 1 m is equal to 100 cm.
So, the density of water in kg/cm³ is 1000 kg/m³ / 1000 = 1 kg/cm³.
Now you can solve for the depth, d:
weight = density_water * g * (10 cm * 10 cm * d)
6.86 N = 1 kg/cm³ * 9.81 m/s² * (10 cm * 10 cm * d)
6.86 N = 0.01 kg * 9.81 m/s² * (d)
6.86 N = 0.0981 kg * d
d = 6.86 N / 0.0981 kg
d ≈ 69.95 cm
Therefore, the correct distance from the top of the wood block to the water is approximately 69.95 cm.