In printing an article of 48,000 words, a printer decides to use two sizes of type. Using the larger type, a printed page contains 1,800 words. Using smaller type, a page contains 2,400 words. The article is allotted 21 full pages in a magazine. How many pages must be in smaller type?
To find out how many pages must be in smaller type, we need to determine the number of pages in larger type first.
Let's assume the number of pages in larger type is x.
In the larger type, each page contains 1,800 words, and the total number of words in the article is 48,000.
So, the number of pages in larger type can be calculated as follows:
x = 48,000 / 1,800
Simplifying this expression:
x = 26.67
Since we cannot have a fraction of a page, we should round this value up to the nearest whole number because we need at least 21 full pages. In this case, we round up to 27.
Now, to find the number of pages in smaller type, we subtract the number of pages in larger type from the total allotted pages:
Number of pages in smaller type = Total allotted pages - Number of pages in larger type
Number of pages in smaller type = 21 - 27
However, since the result is negative, it means that there would be zero pages in smaller type. Therefore, the answer is that there would be zero pages in smaller type.
Let x = pages with 1800 words and y = pages with 2400 words.
From your information:
1800x + 2400y = 48,000
x + y = 21
Then y = 21 - x
Substitute (21-x) for y in the first equation and solve for y. Put the value of y in the second equation to get x. To check, put both values into the first equation.
I'll let you do the calculations.