At work one day Erica received 55 packages. Speedy Delivery delivered 4 times as many as Ralph Express delivered while Ralph delivered 5 times more than Send Quick So how many packaged did each service send
SD=4RE
RE=5SQ
SD+RE+Sq=55
4RE+RE+RE/5=55
5 1/5 RE=55
26/5 RE=55
26RE=275
so something is wrong with the question, it is not an even number.
I think your teacher made an error.
http://www.jiskha.com/display.cgi?id=1258128832
To find out how many packages each service sent, we can break down the information given. Let's assume Send Quick delivered x packages.
According to the information given:
- Ralph Express delivered 5 times more than Send Quick. This means Ralph Express delivered 5x packages.
- Speedy Delivery delivered 4 times as many as Ralph Express. This means Speedy Delivery delivered (4 * 5x) = 20x packages.
We know that Erica received a total of 55 packages. So the sum of packages sent by all three services is x + 5x + 20x = 26x.
Now, we can set up an equation to solve for x:
26x = 55
To solve for x, we divide both sides of the equation by 26:
x = 55/26
Simplifying the above equation:
x ≈ 2.12 (rounded to two decimal places)
Since we can't have a fractional number of packages, we can say that Send Quick delivered approximately 2 packages.
To find out how many packages Ralph Express and Speedy Delivery delivered, we can substitute the value of x:
Ralph Express = 5 * x
Ralph Express = 5 * 2.12
Ralph Express ≈ 10.6 (rounded to one decimal place)
Speedy Delivery = 4 * (5 * x)
Speedy Delivery = 4 * (5 * 2.12)
Speedy Delivery ≈ 42.4 (rounded to one decimal place)
So, Send Quick delivered approximately 2 packages, Ralph Express delivered approximately 10.6 packages, and Speedy Delivery delivered approximately 42.4 packages.