a stone of mass o.5 kg is dropped from a height of 5om.what is the kinetic energy of the stone just before it strikes the ground
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To calculate the kinetic energy (KE) of the stone just before it strikes the ground, we need to use the equation:
KE = (1/2) * m * v^2
where:
- KE is the kinetic energy,
- m is the mass of the stone, and
- v is the velocity of the stone.
First, we need to calculate the velocity of the stone just before it strikes the ground. To do this, we can use the equation for the final velocity of an object in free fall:
v = √(2 * g * h)
where:
- v is the velocity,
- g is the acceleration due to gravity (approximately 9.8 m/s^2), and
- h is the height from which the stone is dropped.
In this case, the height (h) is given as 50m, and the mass (m) is given as 0.5 kg. Let's plug in the values and calculate:
v = √(2 * 9.8 * 50)
= √(980)
= 31.3 m/s (approximately)
Now that we have the velocity, we can calculate the kinetic energy using the first equation:
KE = (1/2) * 0.5 * (31.3)^2
≈ 244.7 Joules
So, the kinetic energy of the stone just before it strikes the ground is approximately 244.7 Joules.