If you are given a 0.27 g piece of sodium metal to react with water, how many moles of HCl would it take to neutralize the sodium hydroxide produced?
Well, I must say, this question has quite the balancing act going on, doesn't it? But don't fret, my dear friend! I'm here to juggle the answer for you.
To calculate the number of moles of HCl needed to neutralize the sodium hydroxide produced, we have to step into the world of chemistry. So, let's dive in!
First, we need to know the balanced equation for the reaction between sodium and water:
2Na + 2H2O → 2NaOH + H2
Since 2 moles of sodium form 2 moles of sodium hydroxide, we need to figure out the number of moles of sodium hydroxide produced from the given mass of sodium.
To do that, we can use the molar mass of sodium (22.99 g/mol) to find the number of moles:
0.27 g of sodium × (1 mol Na / 22.99 g Na) = approximately 0.0117 mol Na
Since 2 moles of sodium form 2 moles of sodium hydroxide, we have:
0.0117 mol Na × (2 mol NaOH / 2 mol Na) = approximately 0.0117 mol NaOH
Now that we know the number of moles of sodium hydroxide produced, we can determine how many moles of HCl are required to neutralize it. Since HCl and NaOH react in a 1:1 ratio, we get:
0.0117 mol NaOH → 0.0117 mol HCl
So, approximately 0.0117 moles of HCl would be needed to neutralize the sodium hydroxide produced. I hope my balancing act brought a smile to your face!
To determine the number of moles of HCl required to neutralize the sodium hydroxide produced, we need to follow these steps:
Step 1: Write the balanced equation for the reaction between sodium metal (Na) and water (H2O):
2Na + 2H2O -> 2NaOH + H2
This equation shows that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide (NaOH) and 1 mole of hydrogen gas (H2).
Step 2: Calculate the number of moles of sodium hydroxide produced from the given mass of sodium metal.
To do this, we need to determine the moles of sodium (Na) first:
molar mass of Na = 22.99 g/mol
moles of Na = mass of Na / molar mass of Na
= 0.27 g / 22.99 g/mol
= 0.0117 mol
Since the balanced equation shows a 1:1 stoichiometric ratio between sodium (Na) and sodium hydroxide (NaOH), 0.0117 moles of sodium will also produce 0.0117 moles of sodium hydroxide.
Step 3: Use the balanced equation to find the moles of HCl required to neutralize the sodium hydroxide.
From the balanced equation, we can see that 2 moles of sodium hydroxide react with 1 mole of HCl.
Therefore, the moles of HCl required = 0.0117 mol / 2 = 0.00585 mol.
So, it would take approximately 0.00585 moles of HCl to neutralize the sodium hydroxide produced.
To solve this problem, we need to follow a series of steps:
Step 1: Determine the moles of sodium metal (Na):
The molar mass of sodium (Na) is 22.99 g/mol. We can use this information to find the number of moles of sodium by dividing the given mass by the molar mass:
moles of Na = mass of Na / molar mass of Na
moles of Na = 0.27 g / 22.99 g/mol
Step 2: Write the balanced chemical equation:
The balanced chemical equation for the reaction between sodium (Na) and water (H2O) is:
2 Na + 2 H2O → 2 NaOH + H2
Step 3: Determine the moles of sodium hydroxide (NaOH) produced:
From the balanced chemical equation, we see that 2 moles of sodium react to form 2 moles of sodium hydroxide. Therefore, we can directly say that the number of moles of sodium hydroxide produced will be equal to the number of moles of sodium:
moles of NaOH = moles of Na
Step 4: Determine the moles of HCl needed to neutralize the sodium hydroxide:
From the balanced chemical equation, we see that for every 2 moles of sodium hydroxide, 1 mole of hydrogen chloride (HCl) is needed to neutralize it. Therefore, the number of moles of HCl needed will be half the number of moles of sodium hydroxide:
moles of HCl = (1/2) * moles of NaOH
By substituting the value obtained in Step 3 into this equation, we can find the moles of HCl required to neutralize the sodium hydroxide produced.
2Na + 2H2O ==> 2NaOH + H2
0.27 g Na = how many moles Na?
0.27/23 = ?? moles Na (I'm using molar mass from my memory so you need to look them up and do them exactly).
How much NaOH is formed?
?? moles Na x (2 moles NaOH/2 moles Na) = ?? moles NaOH.
Now NaOH + HCl ==> H2O + NaCl
So ?? moles NaOH will require ?? (th same) moles HCl.