PHYSICS - urgent

assuming there's no friction of, if two balls (one heavier than the other) are held up the same distance from the ground; the heavier ball will have more G.P.E than the lighter one, n when both are dropped, all the G.P.E can only change to K.E, as there's no friction; wot i'm confused abt is that without air gravity will pull them both at a constant acceleration (9.8m/s, meaning both will have the same speed - but shouldn't the heavier ball be moving faster as it had more G.P.E than the other ball, hence more K.E?

Can sum1 pls calrify?


No. Its higher GPE is proportional to its mass, but so is the kinetic energy that is gets converted to. The mass factor drops out and
g H = V^2/2


I don't get it. U say that the k.E is proportional to mass n then u say the mass factor drops out

Can u plssssssssss explain it clearly?


K.E. = change in P.E.

(1/2)M V^2 = M g H

H is the change in height

M cancels out. It is in both sides of the equation. Do the algebra.

V^2 = 2 g H


NOW THT ANSWERS IT......thank you v much


yes i think so to that if you have for ex:if u have a peace of paper in one hand and you have crumpled paper in the other hand than i think that the crumpled paper will be in the first place because of thegravity on earth.

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asked by Shahrukh

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