A satillite is orbiting the earth at a distance of 1.00X10^3 km above the surface of the earth. What is it's speed?
see the first post I outlined for you.
To calculate the speed of a satellite orbiting the Earth, we can use the formula for the orbital speed:
V = √(G * M / R)
Where:
V is the orbital speed
G is the gravitational constant
M is the mass of the Earth
R is the distance between the satellite and the center of the Earth (not the surface)
First, let's determine the value of these variables:
Gravitational constant (G):
G = 6.67430 × 10^-11 N(m/kg)^2
Mass of the Earth (M):
M = 5.972 × 10^24 kg
Distance above the surface (R):
R = Distance to the center of the Earth + Radius of the Earth
= 1.00 × 10^3 km + 6.371 × 10^3 km
Converting the distance to meters:
R = (1.00 × 10^3 + 6.371 × 10^3) × 10^3 m
= 7.371 × 10^6 m
Now, we can substitute the values into the formula:
V = √(6.67430 × 10^-11 N(m/kg)^2 * 5.972 × 10^24 kg / 7.371 × 10^6 m)
Calculating this expression will give us the speed of the satellite.