how many grams of ethylene would have to be burned to produce 450 kJ of heat?
What is the mass of water that can be heated from 39 C to 80 C by the combustion of 150 g of methane. CH4 + 2O2 => CO2 + 2H2O Delta H= -890kJ
To determine the number of grams of ethylene that need to be burned to produce 450 kJ of heat, we need to use the heat of combustion of ethylene.
The heat of combustion of ethylene is approximately 1411 kJ/mol.
Step 1: Convert the heat of combustion to moles.
The molar mass of ethylene (C2H4) is approximately 28 g/mol. Thus, the number of moles of ethylene required can be found by:
moles = heat / heat of combustion
moles = 450 kJ / 1411 kJ/mol
Step 2: Convert moles to grams.
To find the grams, we can use the molar mass of ethylene:
grams = moles * molar mass
grams = (450 kJ / 1411 kJ/mol) * 28 g/mol
By performing the calculations, the amount of ethylene required is approximately 8.95 grams.
To determine the grams of ethylene that would need to be burned to produce 450 kJ of heat, we need to know the heat of combustion for ethylene. The heat of combustion is the quantity of heat released when one mole of a substance undergoes complete combustion.
The chemical formula for ethylene is C2H4. The balanced equation for the combustion of ethylene is:
C2H4 + 3 O2 -> 2 CO2 + 2 H2O
From the balanced equation, we can see that for every mole of ethylene burned, 2 moles of carbon dioxide (CO2) and 2 moles of water (H2O) are produced.
To find the heat of combustion for ethylene, we can refer to a reliable source such as a chemistry database or textbook. The heat of combustion for ethylene is approximately -1410 kJ/mol.
Now we can calculate the amount of ethylene required to produce 450 kJ of heat.
First, convert the given heat value to moles using the heat of combustion:
450 kJ * (1 mol / -1410 kJ) ≈ -0.319 moles
Since the stoichiometry of the balanced equation shows that 1 mole of ethylene produces 2 moles of CO2, we can determine the moles of ethylene needed:
-0.319 moles * (1 mol C2H4 / 2 mol CO2) ≈ -0.1595 moles
Finally, convert moles to grams using the molar mass of ethylene:
-0.1595 moles * (28.05 g/mol) ≈ -4.49 grams
Therefore, approximately 4.49 grams of ethylene would need to be burned to produce 450 kJ of heat.
You need the heat of combustion for ethylene.
C2H4 + 3O2 ==> 2CO2 + 2H2O
450 kJ/heat combustion per mole = # moles C2H4 burned.
Then # moles C2H4 x molar mass C2H4 = grams C2H4.