The concentration and volume of reagents combined in each trial are listed in the table below:

Trial 00020 M 00020 M H2O(mL)
Fe(NO3)3mL) KSCN (mL)
1 5 2 3
2 5 3 2
3 5 4 1
4 5 5 0

Initially (right after combining and before any reaction occurs) the concentration of SCN– in trial 1 is?

thanks but i figured how to do this

To determine the initial concentration of SCN- in Trial 1, we need to use the information provided in the table:

- Fe(NO3)3 (mL): 5 mL
- KSCN (mL): 2 mL
- H2O (mL): 3 mL

The volume of KSCN in Trial 1 is 2 mL, and its concentration is not given directly in the table. However, we can assume that the concentration of KSCN is also 0.020 M for all trials since it is not specified otherwise.

To calculate the initial concentration of SCN- in Trial 1, we can use the equation:

Initial concentration (SCN-) = (Volume of KSCN / Total volume of the solution) * Concentration of KSCN

Total volume of the solution = Volume of Fe(NO3)3 + Volume of KSCN + Volume of H2O

Let's substitute the values into the equation:

Total volume of the solution = 5 mL (Fe(NO3)3) + 2 mL (KSCN) + 3 mL (H2O)
Total volume of the solution = 10 mL

Initial concentration (SCN-) = (2 mL / 10 mL) * 0.020 M (KSCN)

Calculating this will give us the initial concentration of SCN- in Trial 1.