a conical pendulum is formed by attaching a 500g ball to a 1m long string then allowing the mass to move in a horizontal circle of radius 20 cm.

A) what is the tension of the string?
b) what is the balls angular speed in rpm?

To find the tension of the string in the conical pendulum, we need to consider the forces acting on the ball.

a) The tension, T, in the string provides the centripetal force to keep the ball moving in a horizontal circle. We can calculate this tension using the following formula:

T = (m * v^2) / r

where:
m = mass of the ball = 500g = 0.5 kg
v = velocity of the ball
r = radius of the circle = 20 cm = 0.2 m

To find the velocity of the ball, we need to consider the circular motion. In circular motion, the centripetal force required to keep an object moving in a circle is given by:

F_c = m * a_c

where:
F_c = centripetal force
a_c = centripetal acceleration

Centripetal acceleration can be calculated using:

a_c = v^2 / r

By equating the two equations for centripetal force, we have:

T = m * a_c
T = m * (v^2 / r)

Since a_c = v^2 / r, we can rewrite the equation as:

T = m * a_c

Now, substituting the given values, we have:

T = (0.5 kg) * (v^2 / 0.2 m)

We need to find the value of v. The formula for velocity can be derived from the period of circular motion:

v = 2 * π * r / T

where T is the time period for one complete revolution of the ball, which can be obtained using the formula:

T = 2 * π * √(r / g)

where g is the acceleration due to gravity.

Substituting the given values into these formulas, we can find the tension.

b) To find the ball's angular speed in RPM (revolutions per minute), we can use the formula:

ω = v / r

where:
ω = angular speed
v = velocity of the ball
r = radius of the circle

We can then convert the angular speed to RPM by multiplying by a factor of 60, as there are 60 minutes in an hour.

Let's calculate these values step by step.

To find the tension in the string and the ball's angular speed in rpm, we can use the principles of centripetal force and rotational motion. Let's break it down step by step:

a) To find the tension in the string, we need to consider the forces acting on the ball. In circular motion, the centripetal force (F_c) is responsible for keeping the ball moving in a circular path. In this case, tension (T) in the string provides the necessary centripetal force. The formula for centripetal force is given by:

F_c = (m * v^2) / r

Where:
- F_c is the centripetal force
- m is the mass of the ball
- v is the speed of the ball
- r is the radius of the circular path

Since the ball is moving in a horizontal circle, the speed (v) can be determined using the formula:

v = ω * r

Where:
- ω is the angular velocity of the ball

Substituting this into the centripetal force formula, we get:

F_c = (m * (ω * r)^2) / r
= m * ω^2 * r

Now, we can substitute the given values into the equation:
- m = 500g = 0.5kg
- r = 20cm = 0.2m

F_c = 0.5kg * ω^2 * 0.2m

Since we want to find the tension (T) in the string and T represents F_c:

T = F_c = 0.5kg * ω^2 * 0.2m

b) To find the ball's angular speed in rpm, let's convert the angular speed from radians per second (rad/s) to revolutions per minute (rpm).

1 revolution = 2π radians
1 minute = 60 seconds

We have:

ω (in rad/s) = 2π * f

Where:
- f is the frequency of rotation

Since frequency (f) is the number of revolutions per second, it can be calculated as:

f = v / (2π * r)

Substituting ω = 2π * f into the equation, we get:

ω = 2π * (v / (2π * r))
= v / r

Now we can substitute v = ω * r (from the previous explanation) into the equation:

ω = (ω * r) / r

Using the given values, we can calculate ω:

ω = (0.2m) / (1m)
= 0.2 rad/s

To convert ω from rad/s to rpm, we multiply it by (60 / 2π):

angular speed (in rpm) = (0.2 rad/s) * (60 / 2π)

Now, you can calculate the tension in the string (T) and the ball's angular speed in rpm using the formulas and given values provided above.

A) Perform a vector addition of the weight and the mass x (centripetal acceleration). The two forces act in perpendicular directions, and the resultant is the tension, T.

B) T sin A = M V^2/R, from a horizontal force balance. Solve for V.

A is the angle of the string from vertical. Solve for V

Use V and R to get the rpm.

2 pi R/T = V
where T is the time required for the ball to go around once, in seconds.

RPM = 60/T