What is the gas pressure inside the box shown in the figure?

I have a picture but website wouldn't allow me to post the link for the picture.
So I am trying my best to describe it.
it is a u-shape tube and it is holding mercury in it. One side has 16cm of mercury and other side has 6cm.
what i did was p_gas:
101300+(9.81*13600*.16*.06)..doesn't work

difference between height is 10 cm so use 0.1 instead of 0.6 and you should get 88000

Hey, so are we sure this is the answer guys?

bro why did you say that. clearly, you are wrong. I am struggling with my physics problem and u think that's a joke?

i got 13341.6 ...it is incorrect

i figured it out..thanks for helping me

Annie, how can you say that...it is my question i am still working on it

sorry Ana... i missed typed it...again i apologize

To determine the gas pressure inside the box shown in the figure, you need to consider the relationship between the pressure of the gas and the height difference of the mercury levels in the u-shaped tube. This relationship is described by Pascal's law.

Pascal's law states that the pressure of a fluid (in this case, mercury) in an enclosed system is transmitted equally in all directions. In your case, the pressure of the gas inside the box is balanced by the pressure of the mercury columns in the u-shaped tube.

To calculate the gas pressure, you need to use the equation:
P_gas = P_atm + (ρ * g * h)

Here:
P_gas is the gas pressure inside the box (what you're trying to find),
P_atm is the atmospheric pressure (usually taken as 101,300 Pa at sea level),
ρ is the density of the fluid (in this case, mercury, which is approximately 13,600 kg/m^3),
g is the acceleration due to gravity (approximately 9.81 m/s^2), and
h is the height difference of the mercury columns in meters.

In your description, you mentioned that one side of the u-shaped tube has 16 cm of mercury, while the other side has 6 cm. To use the equation, you need to convert the heights to meters.

So, h1 = 16 cm = 0.16 m (height of one side)
and h2 = 6 cm = 0.06 m (height of the other side).

Substituting the values into the equation, you can calculate the gas pressure as follows:
P_gas = P_atm + (ρ * g * (h1 - h2))
= 101,300 Pa + (13,600 kg/m^3 * 9.81 m/s^2 * (0.16 m - 0.06 m))
= 101,300 Pa + (13,600 kg/m^3 * 9.81 m/s^2 * 0.10 m)
= 101,300 Pa + 13,356 Pa
= 114,656 Pa

Therefore, the gas pressure inside the box is approximately 114,656 Pa, considering the given heights of the mercury columns in the u-shaped tube.

There should be mercury in both sides of the tube, with a higher column height on the side opposite to the side with the gas.

The gas pressure equals
P= (mercury density) g h,
where h is the difference in the mecruty column heights.

You do not have to add 101300 (atmosheric pressure) to get the absolute pressure with a u-tube manometer such as this.

P = 9.81 m/s^2*13600 kg/m^3*(.16-.06) m