How many grams of sodium chloride are there in 55.00 Ml of a 1.90 M aqueous solution of sodium chloride? any idea.

2. What is the concentration of chloride ions in a 0.193 M solution of potassium chloride?..heeeeeeeeeeeelp.

1.

moles NaCl = M x L
grams NaCl = moles x molar mass.

2.
You have 1 mole Cl ions in 1 mole KCl; therefore, the concn of Cl ions in 0.193 M KCl must be 0.193 M.

To find the number of grams of sodium chloride in a solution, you need to use the formula:

grams = volume (in liters) x concentration (in M) x molar mass (in g/mol)

1. For the first question:

Step 1: Convert milliliters (mL) to liters (L).
55.00 mL = 55.00/1000 L = 0.055 L

Step 2: Calculate the number of grams of sodium chloride using the formula mentioned above.
grams = 0.055 L x 1.90 M x molar mass of sodium chloride

The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol.

grams = 0.055 L x 1.90 M x 58.44 g/mol

Calculate the result to get the exact grams of sodium chloride in the solution.

2. For the second question:

To find the concentration of chloride ions in a solution, you need to consider the dissociation of potassium chloride (KCl) in water. KCl dissociates into one potassium ion (K+) and one chloride ion (Cl-).

Since potassium chloride dissociates into two ions, the concentration of chloride ions is the same as the concentration of potassium chloride.

Therefore, the concentration of chloride ions in a 0.193 M solution of potassium chloride is 0.193 M.

Sure, I can help you with both questions step-by-step:

1. How many grams of sodium chloride are there in 55.00 mL of a 1.90 M aqueous solution of sodium chloride?
To find the grams of sodium chloride, we need to use the formula:

grams = volume (in liters) × concentration (in M) × molar mass (in g/mol)

The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol.

First, convert the volume from milliliters (mL) to liters (L):
55.00 mL = 55.00 / 1000 L = 0.055 L

Now, we can calculate the grams of sodium chloride:
grams = 0.055 L × 1.90 M × 58.44 g/mol = 6.253 g

Therefore, there are approximately 6.253 grams of sodium chloride in 55.00 mL of a 1.90 M aqueous solution of sodium chloride.

2. What is the concentration of chloride ions in a 0.193 M solution of potassium chloride?
Since potassium chloride (KCl) dissociates into potassium ions (K⁺) and chloride ions (Cl⁻), the concentration of chloride ions is the same as the concentration of potassium chloride.

Therefore, the concentration of chloride ions in a 0.193 M solution of potassium chloride is 0.193 M.

Please let me know if you need further assistance!