What value of p are
2p-1,7 and 3P three consecutive terms of ARITHMETIC PROGRESSION
To find the value of "p" in the given scenario, we can use the concept of an arithmetic progression (AP). In an AP, the difference between any two consecutive terms is constant.
In this case, we are given that the three consecutive terms are 2p - 1, 7, and 3p. We can write the equation for the difference between consecutive terms as follows:
Common Difference = Second Term - First Term = Third Term - Second Term
Using the values given, we can substitute them into the equation:
7 - (2p - 1) = 3p - 7
Now, let's solve this equation step by step:
7 - 2p + 1 = 3p - 7
8 - 2p = 3p - 7
Next, we want to isolate the "p" terms on one side of the equation. We can do this by moving the 3p term to the right side and the 8 term to the left side:
8 + 7 = 3p + 2p
15 = 5p
Finally, we can solve for "p" by dividing both sides of the equation by 5:
15 / 5 = p
3 = p
Therefore, the value of "p" is 3.
What value of p are 2p-1, 7 and 3p three consecutive terms of an ARITHMETIC PROGRESSION?
Letting a = the common difference, we can write
1--(7 - a) = 2P - 1 and
2--(7 + a = 3p
Adding yields 14 = 5p - 1 from which p = 3 making the 3 terms 5, 7 and 9.