how many grams of Sb2S3 will contain 4.80 moles of S
You will need 4.80/3 = 1.60 moles of Sb2S3, since each molecule has three S atoms. Convert that to grams of Sb2S3.
To find the mass of Sb2S3 in grams that contains 4.80 moles of S, you will need to know the molar mass of Sb2S3.
The molar mass of Sb (antimony) is approximately 121.76 g/mol, and the molar mass of S (sulfur) is approximately 32.06 g/mol. Since Sb2S3 contains two antimony atoms and three sulfur atoms, you can calculate the molar mass of Sb2S3.
Molar mass of Sb2S3:
(2 × molar mass of Sb) + (3 × molar mass of S)
= (2 × 121.76 g/mol) + (3 × 32.06 g/mol)
= 243.52 g/mol + 96.18 g/mol
= 339.70 g/mol
Now, you can use the molar mass of Sb2S3 to find the mass of 4.80 moles of S.
Mass of Sb2S3 = (moles of S) × (molar mass of Sb2S3)
= 4.80 moles × 339.70 g/mol
= 1631.76 grams (rounded to the nearest hundredths place)
Therefore, 4.80 moles of S will require approximately 1631.76 grams of Sb2S3.