IN A TUG OF WAR, 5 DONKEYS ARE EXACTLY EQUAL TO 2 ELEPHANTS. IN ANOTHER TUG OF WAR, 3 ELEPHANTS ARE EQUAL TO 1 CAR. WHICH TEAM SHOULD WIN IF A CAR AND 3 DONKEYS ARE MATCHED AGAINST 4 ELEPHANTS?
1car + 3 donkeys = 4.2 elephants, so they win.
5d = 2e
3e = 1c
1c+3d ? 4e
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d = (2/5)e
c = (3/1)e
1(3e)+3((2/5e)) = 4.2e > 4e
So, 1 car + 3 donkeys equals to 4.2 elephants, so they win.
The donkeys and the car win because 2.5 donkeys equal 1 elephant
so it is a tie
To determine which team should win in this scenario, let's break down the information provided step by step.
First, we are given that 5 donkeys are equal to 2 elephants in a tug of war. So, we can establish the following equivalence:
5 donkeys = 2 elephants
Next, we are told that 3 elephants are equal to 1 car. This can be represented as:
3 elephants = 1 car
Now, we need to compare the team with 1 car and 3 donkeys to the team with 4 elephants. We can convert both teams into the same unit (either donkeys or elephants) to make a fair comparison.
Since we already have an equivalence between donkeys and elephants, let's convert the team with 1 car and 3 donkeys into elephants:
To convert 3 donkeys into elephants, we can use the earlier equivalence: 5 donkeys = 2 elephants
So, we can calculate:
3 donkeys = (3/5) * 2 elephants
= 6/5 elephants
Therefore, the team with 1 car and 3 donkeys is equal to 6/5 elephants.
Now let's compare this team to the team with 4 elephants:
Team with 1 car and 3 donkeys = 6/5 elephants
Team with 4 elephants
Since 6/5 is less than 4, the team with 1 car and 3 donkeys is at a disadvantage when compared to the team with 4 elephants.
Therefore, the team with 4 elephants should win if a car and 3 donkeys are matched against them.
Try this.
5D = 2E
3E = 1 car
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Since E are common, let's make them equal (by multiply 1 by 3 and 2 by 2)
3*5D = 3*2E and
2*3E = 2*1 car
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So we have
15D=6E and
6E = 2 car
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Now the 6E are common; therefore,
15D = 2 Car or
7.5D = 1 Car
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The question asks about
3D ----- 1 Car
Which do you think?