60 cm^3 of gasoline are mixed with 55 cm^3 of water. What is the average density of the mixture? answers in meters
i did (.6*680)+(.55*1000)
then divided by 95...is this workable?
if i have a question with a picture then how can i post it?
You should have divided by 1.15. That will give you the answer in kg/m^3
Actually, you are mixing up volumes in liters and densities in kg/m^3, but as long as the denominator volume is in liters (as are the numerator volumes), you will get the right answer in kg/m^3.
A uniform ladder which is 10m long and weighs 300N, leans with its upper end against a smooth vertical wall and its lower end on rough horizontal ground. A man weighing 700N stands on the ladder at point of 6m above the ground. Calculate the magnitutes and the directions of the forces exerted on the ladder by: (a) the wall (b) the ground
To find the average density of the mixture, you need to take into account the densities of gasoline and water. The density of gasoline is typically around 680 kg/m^3, and the density of water is approximately 1000 kg/m^3.
First, convert the volumes from cm^3 to m^3. Divide each volume by 100^3 to convert from cm^3 to m^3.
Gasoline volume: 60 cm^3 = 60 / (100^3) m^3 = 0.00006 m^3
Water volume: 55 cm^3 = 55 / (100^3) m^3 = 0.000055 m^3
Next, calculate the total mass of the mixture by multiplying the volume of gasoline by its density, and the volume of water by its density:
Gasoline mass = 0.00006 m^3 * 680 kg/m^3 = 0.0408 kg
Water mass = 0.000055 m^3 * 1000 kg/m^3 = 0.055 kg
Add the masses of gasoline and water together to get the total mass of the mixture:
Total mass = 0.0408 kg + 0.055 kg = 0.0958 kg
Now, divide the total mass by the total volume to calculate the average density:
Average density = Total mass / Total volume = 0.0958 kg / (0.00006 m^3 + 0.000055 m^3)
After performing the calculation, the average density of the mixture should be expressed in kg/m^3.