A manufacturing company has determined that the cost of labor for producing x transmissions is:
L(x) = 0.3x^2 + 400x + 550 dollars,
while the cost of materials is
M(x) = 0.1x^2 + 50x + 800 dollars.
Need to write a polynomial T(x) that represents the total cost of materials and labor for producing x transmissions.
Need to evaluate the total cost of polynomial for x=500
Need to find the cost of labor for 500 transmissions and the cost of materials for 500 transmissions.
(Any help would greatly be appreciated. I really don't understand any of this)
To find the polynomial T(x) that represents the total cost of materials and labor for producing x transmissions, you need to add the cost of labor (L(x)) and the cost of materials (M(x)) together.
T(x) = L(x) + M(x)
Now, substitute the given expressions for L(x) and M(x) into the equation:
T(x) = 0.3x^2 + 400x + 550 + 0.1x^2 + 50x + 800
Simplify the expression:
T(x) = 0.3x^2 + 0.1x^2 + 400x + 50x + 550 + 800
Combine like terms:
T(x) = 0.4x^2 + 450x + 1350
To evaluate the total cost of the polynomial T(x) for x = 500, substitute 500 into the equation:
T(500) = 0.4(500)^2 + 450(500) + 1350
Calculate the value of T(500):
T(500) = 0.4 * 250000 + 450 * 500 + 1350
T(500) = 100000 + 225000 + 1350
T(500) = 326,350 dollars
Therefore, the total cost of producing 500 transmissions is $326,350.
To find the cost of labor for 500 transmissions, substitute 500 into the labor cost equation L(x):
L(500) = 0.3(500)^2 + 400(500) + 550
Calculate the value of L(500):
L(500) = 0.3 * 250000 + 400 * 500 + 550
L(500) = 75000 + 200000 + 550
L(500) = 275,550 dollars
Therefore, the cost of labor for producing 500 transmissions is $275,550.
To find the cost of materials for 500 transmissions, substitute 500 into the material cost equation M(x):
M(500) = 0.1(500)^2 + 50(500) + 800
Calculate the value of M(500):
M(500) = 0.1 * 250000 + 50 * 500 + 800
M(500) = 25000 + 25000 + 800
M(500) = 50,800 dollars
Therefore, the cost of materials for producing 500 transmissions is $50,800.
To write a polynomial T(x) that represents the total cost of materials and labor for producing x transmissions, we need to add the cost of labor and the cost of materials.
The cost of labor is represented by L(x) = 0.3x^2 + 400x + 550 dollars.
The cost of materials is represented by M(x) = 0.1x^2 + 50x + 800 dollars.
Therefore, the total cost polynomial T(x) is:
T(x) = L(x) + M(x).
To evaluate the total cost polynomial for x = 500, substitute x = 500 into T(x):
T(500) = L(500) + M(500).
Next, let's find the cost of labor for 500 transmissions and the cost of materials for 500 transmissions.
To find the cost of labor for 500 transmissions, plug in x = 500 into the cost of labor equation:
L(500) = 0.3(500)^2 + 400(500) + 550
To find the cost of materials for 500 transmissions, plug in x = 500 into the cost of materials equation:
M(500) = 0.1(500)^2 + 50(500) + 800
By evaluating these equations, you will get the specific values for the cost of labor and the cost of materials for 500 transmissions.