Calculate the average disappearance of A between t=0 min and t=10 min in units of M/s.

0 min there are .065 moles of A
10 min there are .051 moles of A
20 min there are .042 moles of A
30 min there are .036 moles of A
40 min there are .031 moles of A

The total volume is 100.0 mL.

The equation given is: A -> B

I know that to get Molarity you divide the number of moles by the total volume in Liters (which means a conversion of mL to Liters). Also that minutes would have to be converted to seconds by multiplying by 60.

To calculate the average disappearance of A between t=0 min and t=10 min in units of M/s, you can follow these steps:

Step 1: Convert the total volume from mL to liters:
Total volume = 100.0 mL = 100.0 mL / 1000 mL/L = 0.1 L

Step 2: Calculate the change in the number of moles of A between t=0 min and t=10 min:
Change in moles of A = Initial moles of A - Final moles of A
= 0.065 moles - 0.051 moles
= 0.014 moles

Step 3: Convert minutes to seconds:
Time interval = t final - t initial = 10 min - 0 min = 10 min * 60 s/min = 600 s

Step 4: Calculate the average disappearance rate of A:
Average disappearance rate = Change in moles of A / Time interval
= 0.014 moles / 600 s
≈ 0.000023 moles/s

Step 5: Calculate the average disappearance rate in units of M/s:
Average disappearance rate in M/s = Average disappearance rate / Total volume
≈ 0.000023 moles/s / 0.1 L
≈ 0.00023 M/s

Therefore, the average disappearance of A between t=0 min and t=10 min is approximately 0.00023 M/s.

To calculate the average disappearance of A between t=0 min and t=10 min in units of M/s, we need to find the rate at which A is disappearing over that time interval.

First, let's calculate the change in moles of A between t=0 min and t=10 min:
Change in moles of A = (moles of A at t=0 min) - (moles of A at t=10 min)
Change in moles of A = 0.065 moles - 0.051 moles
Change in moles of A = 0.014 moles

Next, let's convert the time interval from minutes to seconds:
Time interval = (10 min - 0 min) * 60 seconds/min
Time interval = 600 seconds

Now, let's convert the total volume from mL to liters:
Total volume = 100.0 mL / 1000 mL/L
Total volume = 0.1 L

Now, we can calculate the average disappearance rate of A in M/s:
Average disappearance rate = (Change in moles of A) / (Time interval * Total volume)
Average disappearance rate = 0.014 moles / (600 seconds * 0.1 L)
Average disappearance rate = 0.014 moles / 60 L⋅s^-1
Average disappearance rate ≈ 2.33 × 10^-4 M/s

Therefore, the average disappearance of A between t=0 min and t=10 min is approximately 2.33 × 10^-4 M/s.

I supspect the M in M/s is moles per second, not concentration decrease. No volume was specified. Frankly, if this is what is desired, it should have said mol/s . But I do think that is what it meant.

.014 moles disappeared in the first 600 sec, or an average rate of 6.67millimoles/sec