To get an A in history, a student must score an average of 90 on four papers. Scores on the first three papers were 92, 83, and 88. What is the lowest score that a student can make on the last paper and still get an A?
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the average of the four test is 90, one way to calculate the min score for all papers (360) then take away the result for the first 3 paper. hope this helps.
simplify 9qt 9pt
To determine the lowest score a student can make on the last paper and still get an A, we need to calculate the average score of the four papers.
Here's how you can do that step-by-step:
Step 1: Add up the scores of the first three papers: 92 + 83 + 88 = 263.
Step 2: To find the average, divide the sum by the number of papers: 263 ÷ 3 = 87.67 (rounded to two decimal places).
Step 3: Now, we know that to receive an A, the student needs to score an average of 90 across the four papers. So, we need to find the lowest possible score on the last paper to reach an average of 90.
Step 4: Multiply the desired average score (90) by the number of papers (4): 90 × 4 = 360.
Step 5: Subtract the sum of the first three papers' scores (263) from the desired total (360): 360 - 263 = 97.
Therefore, the lowest score that a student can make on the last paper and still get an A is 97.