Find the molarity of a salt water solution containing 0.27 mol NaCl in 150g of H2O.
My work: 0.27 mol NaCl/150 g x 1000g/1kg = 1.8 M
is this correct, i wasn't really sure what to do...
Yes.
Thank you so much!!!
Yes, your calculation is correct! Here's how you arrived at the molarity of the salt water solution:
Molarity (M) is defined as the number of moles of solute dissolved in one liter of solution. To find the molarity, you need to find the number of moles of NaCl (solute) and the volume of the solution.
Step 1: Find the number of moles of NaCl:
You are given that the solution contains 0.27 mol of NaCl.
Step 2: Find the volume of the solution:
The volume of the solution is given as 150g of water (H2O). However, to use this in our calculation, we need to convert it to liters.
To convert grams to kilograms, divide by 1000:
150g รท 1000 = 0.15 kg
The density of water is 1 g/mL or 1 kg/L, so the volume of water in liters is also 0.15 L.
Step 3: Calculate the molarity:
Molarity (M) = moles of solute / volume of solution (in liters)
M = 0.27 mol NaCl / 0.15 L H2O = 1.8 M
Therefore, the molarity of the salt water solution is 1.8 M.