Compare the bond enthalpies of the nitrogen-nitrogen single, double, and triple bonds. Based on this information, what is the average pi-bond contribution to bond enthalpy?
single: 163kj/mol
double: 418kj/mol
triple: 941kj/mol
941 - 418 = 523
418 - 163 = 255
523 + 255 = 778
778/2 = 389 kj/mol
(did it on mastering chemistry, answer was correct)
Well, let's do some math... or mirth, whichever you prefer! The bond enthalpies of nitrogen-nitrogen bonds go as follows:
- The nitrogen-nitrogen single bond has an enthalpy of 163kJ/mol. It's like a conservative politician; it takes one step at a time, not rushing into things.
- The nitrogen-nitrogen double bond has an enthalpy of 418kJ/mol. It's like a middle-aged person trying to decide between having one scoop or two scoops of ice cream - a bit indecisive, but still pretty strong and flavorful.
- The nitrogen-nitrogen triple bond is quite the firecracker, with an enthalpy of 941kJ/mol. It's like a speeding bullet, supercharged with energy and ready to make an explosive impact.
Now, to find the average pi-bond contribution to bond enthalpy, here's the sneaky part: The single bond doesn't have a pi bond, the double bond has one pi bond, and the triple bond has two pi bonds.
So, we'll add up the enthalpies of the double and triple bonds, and divide by the total number of pi bonds (which is three, since two pi bonds in the triple bond and one in the double bond).
(418kJ/mol + 941kJ/mol) / 3 = 453.0kJ/mol
So, the average pi-bond contribution to bond enthalpy is approximately 453.0 kJ/mol. These pi bonds are quite the energy boosters, it seems!
To compare the bond enthalpies of the nitrogen-nitrogen single, double, and triple bonds, we can simply look at their respective values:
- Single bond: 163 kJ/mol
- Double bond: 418 kJ/mol
- Triple bond: 941 kJ/mol
To determine the average pi-bond contribution to bond enthalpy, we can subtract the single bond enthalpy from the double and triple bond enthalpies, respectively.
For the double bond:
Average pi-bond contribution = Bond enthalpy of double bond - Bond enthalpy of single bond
= 418 kJ/mol - 163 kJ/mol
= 255 kJ/mol
For the triple bond:
Average pi-bond contribution = Bond enthalpy of triple bond - Bond enthalpy of single bond
= 941 kJ/mol - 163 kJ/mol
= 778 kJ/mol
Therefore, the average pi-bond contribution to bond enthalpy is 255 kJ/mol for the double bond and 778 kJ/mol for the triple bond.
To compare the bond enthalpies of the nitrogen-nitrogen single, double, and triple bonds, we look at the given values:
Single bond enthalpy: 163 kJ/mol
Double bond enthalpy: 418 kJ/mol
Triple bond enthalpy: 941 kJ/mol
To find the average pi-bond contribution to bond enthalpy, we first need to understand the concept of pi bonds.
In a double bond, there is one sigma bond and one pi bond. In a triple bond, there is one sigma bond and two pi bonds. Since a sigma bond is always present in both double and triple bonds, we can calculate the pi-bond contribution by subtracting the sigma bond enthalpy from the total bond enthalpy.
For the double bond:
Pi-bond contribution = Total bond enthalpy - Sigma bond enthalpy
Pi-bond contribution = 418 kJ/mol - 163 kJ/mol
Pi-bond contribution = 255 kJ/mol
For the triple bond:
Pi-bond contribution = Total bond enthalpy - 2 x Sigma bond enthalpy
Pi-bond contribution = 941 kJ/mol - 2 x 163 kJ/mol
Pi-bond contribution = 941 kJ/mol - 326 kJ/mol
Pi-bond contribution = 615 kJ/mol
Now, to find the average pi-bond contribution, we take the sum of the pi-bond contributions for the double and triple bonds and divide it by the number of bonds considered (which is two in this case, one double bond and one triple bond):
Average pi-bond contribution = (Pi-bond contribution for double bond + Pi-bond contribution for triple bond) / Number of bonds
Average pi-bond contribution = (255 kJ/mol + 615 kJ/mol) / 2
Average pi-bond contribution = 870 kJ/mol / 2
Average pi-bond contribution = 435 kJ/mol
Therefore, the average pi-bond contribution to the bond enthalpy is 435 kJ/mol.