ive calculated the amount of change for an enzyme controlled reaction as 1.5625 x 10^-8 mol.min-1 and ive been asked to find the activity of the enzyme in micromoles product formed per min per mg of enzyme how do i do this
i have 10 micro litres of a 5mg ml -1 of the enzyme ???
Any help/explanation would be appreciated !!
10E-6liters*5E-3g/1E-3l= 50micrograms
product/(min*mg)= 1.5625E-8mol/(min*.050mg)
= 3.125E-7 mol/min*mg
Now you want that in micro moles..
= .3125micromole/min*mg
check my calcs.
To find the activity of the enzyme in micromoles of product formed per minute per milligram (mg) of enzyme, you need to follow these steps:
Step 1: Convert the enzyme concentration from mg/mL to mg/µL:
Since you have 10 µL of a 5 mg/mL enzyme solution, multiply 10 µL by 5 mg/mL. This gives you 50 mg of enzyme in the 10 µL sample.
Step 2: Convert the enzyme concentration from mg/µL to mg/mL:
Since the enzyme concentration is given as mg/µL and the activity is measured in µmoles of product per minute per mg of enzyme, we need the concentration in mg/mL. Since 1 mL is equivalent to 1000 µL, divide 50 mg by 1000 µL to get 0.05 mg/mL.
Step 3: Calculate the micromoles of product formed per minute:
To find the micromoles of product formed per minute, multiply the change in moles per minute (1.5625 x 10^-8 mol/min) by 10^6 to convert from mol/min to µmol/min. This gives you 15.625 µmol/min.
Step 4: Calculate the activity:
To calculate the activity, divide the micromoles of product formed per minute (15.625 µmol/min) by the enzyme concentration in mg/mL (0.05 mg/mL). This gives you 312.5 µmol/min per mg of enzyme.
Therefore, the activity of the enzyme in micromoles product formed per minute per milligram of enzyme is 312.5 µmol/min per mg.