ive calculated the amount of change for an enzyme controlled reaction as 1.5625 x 10^-8 mol.min-1 and ive been asked to find the activity of the enzyme in micromoles product formed per min per mg of enzyme how do i do this

i have 10 micro litres of a 5mg ml -1 of the enzyme ???

Any help/explanation would be appreciated !!!

Thank you

To calculate the activity of the enzyme in micromoles per minute per milligram of enzyme, you need to follow these steps:

Step 1: Convert the volume of enzyme solution from microliters to liters.
- Given: 10 μL (microliters)
- Conversion: 1 L = 1,000,000 μL
- Calculation: 10 μL / 1,000,000 = 0.00001 L

Step 2: Calculate the amount of enzyme in moles.
- Given: Concentration of enzyme solution = 5 mg/mL
- Calculation: 5 mg/mL × 0.00001 L = 0.00005 moles

Step 3: Convert the amount of enzyme from moles to milligrams.
- Calculation: 0.00005 moles × 1000 mg/mole = 0.05 mg

Step 4: Calculate the activity of the enzyme.
- Given: Change in moles per minute = 1.5625 × 10^-8 mol.min^-1
- Calculation: (1.5625 × 10^-8 mol.min^-1) / (0.00005 moles) = 3.125 × 10^-4 μmol.min^-1

Step 5: Convert the activity to micromoles per minute per milligram of enzyme.
- Calculation: (3.125 × 10^-4 μmol.min^-1) / (0.05 mg) = 6.25 μmol.min^-1.mg^-1

So, the activity of the enzyme is 6.25 micromoles per minute per milligram of enzyme.