A skier leaves the end of a ramp with a velocity of 25.3 m/s and lands 50.3 m from the base of the ramp. How high is the end of the ramp from the ground?

It would depend on the intial angle of the velocity of the skier.

To find the height of the end of the ramp from the ground, we can use the equations of motion.

We have the initial velocity (u) of the skier as 25.3 m/s. We also have the horizontal distance (x) covered by the skier as 50.3 m.

First, let's find the time (t) the skier is in the air. We can use the equation:

x = u * t + (1/2) * a * t^2

Since the acceleration (a) of the skier in the horizontal direction is zero, the equation becomes:

x = u * t

Rearranging the equation, we get:

t = x / u

Substituting the given values, we find:

t = 50.3 m / 25.3 m/s
t ≈ 1.988 seconds

Now, let's find the vertical distance (h) covered by the skier during this time. We can use the equation:

h = (1/2) * g * t^2

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the values, we get:

h = (1/2) * 9.8 m/s^2 * (1.988 s)^2
h ≈ 19.21 meters

Therefore, the height of the end of the ramp from the ground is approximately 19.21 meters.