a 0.02kg arrow hits the target at a speed of 2000m/s 5 seconds after it leaves the bow. With what force does it hit the target?
can you help me do this
Of course! To calculate the force with which the arrow hits the target, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
In this case, the mass of the arrow is given as 0.02kg, and we need to find the acceleration. To find the acceleration, we can use the equation of motion:
v = u + at
Where:
- v is the final velocity (2000m/s),
- u is the initial velocity (which we need to find),
- a is the acceleration (which we need to find),
- t is the time taken (5 seconds).
Since the arrow starts from rest (u = 0), the equation simplifies to:
v = at
Now, we can solve for acceleration:
a = v / t
a = 2000m/s / 5s
a = 400m/s²
Now that we have the acceleration, we can calculate the force:
F = m * a
F = 0.02kg * 400m/s²
F = 8N
Therefore, the arrow hits the target with a force of 8 Newtons.