Physics

A 2.2 m-long string is fixed at both ends and tightened until the wave speed is 50 m/s.What is the frequency of the standing wave shown in the figure?
picture has 6 waves

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  1. If it is truly six waves, then the 2.2m is six wavelengths long.

    f*Lambda=50

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    bobpursley
  2. how did you arrive at 50 because picture might have 7 nodes

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  3. 50 was given as wavespeed.
    I cant determine how many wavelengths the string is, you will have to do that.

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    bobpursley
  4. but how do i do it

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  5. Count the cycles. From equilibrium up to the crest, down the trough, and back to equilibrium (like a complete sinusoidal wave)--that is one cycle.

    Find the time: the distance of the string, divide it by the speed. This is the basic concept of velocity=displacement/time. You just solve for time.

    You have seconds and you have cycles. What is frequency? Cycles per second. There.

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