a student found the percent water in CaCl2*6H2O to be 45.5%. What's the experimental error?
Is it 7.7%?
Oh, we're diving into chemistry, how refreshing! Now, let's calculate that experimental error, shall we?
To find the experimental error, we can take the absolute value of the difference between the experimental value and the accepted value, divided by the accepted value, and then multiply it by 100.
So, if the student found the percent water in CaCl2*6H2O to be 45.5%, and let's assume the accepted value is 50%, we can calculate the experimental error as follows:
(50% - 45.5%) / 50% * 100% = 9%
So, it seems like the experimental error here is approximately 9%, not 7.7%. But hey, don't let that discourage you! Chemistry can be a bit tricky sometimes, but keep experimenting with a sprinkle of humor, and you'll get it right!
To calculate the experimental error, we need to compare the measured value (45.5%) with the theoretical value. The theoretical percent water in CaCl2·6H2O is 44.04%.
To find the experimental error, use the following formula:
Experimental Error = (Measured Value - Theoretical Value) / Theoretical Value * 100
Substituting the values:
Experimental Error = (45.5% - 44.04%) / 44.04% * 100
Experimental Error = 1.46% / 44.04% * 100
Experimental Error ≈ 3.318%
Therefore, the experimental error is approximately 3.318%, not 7.7%.
To determine the experimental error, we need to compare the calculated value with the experimental value.
First, let's calculate the theoretical percent of water in CaCl2*6H2O:
CaCl2 has a molar mass of 110.98 g/mol.
H2O has a molar mass of 18.02 g/mol.
The molar mass of CaCl2*6H2O is (110.98 g/mol * 1) + (18.02 g/mol * 6) = 238.34 g/mol.
The percent water in the compound can be calculated using the formula:
Percent water = (mass of water / mass of the hydrate) * 100
Let's assume the mass of the hydrate used in the experiment is 100 g. Therefore, the mass of water in CaCl2*6H2O is:
(45.5 / 100) * 100 g = 45.5 g
The percent water calculated theoretically is:
(45.5 g / 100 g) * 100 = 45.5%
Now, let's compare this theoretical value with the experimental value of 45.5%.
The experimental error can be calculated using the formula:
Experimental error = |(experimental value - theoretical value) / theoretical value| * 100
Substituting the values, we get:
Experimental error = |(45.5% - 45.5%) / 45.5%| * 100 = 0%
Therefore, the experimental error in this case is 0%, not 7.7%.