f'(x) = (x^2-1)/x

sorry, i meant what is the antiderivative of f'(x) = (x^2-1)/x

Write f(x) as f(x) = x - 1/x, and integrate it one term at a time. The integral (or "antiderivative", if you insist on using that term) of x is (x^2)/2. The integral of -1/x is -ln x. An arbitrary constant term can be added to the integral.

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