f'(x) = (x^2-1)/x

asked by Reen
  1. sorry, i meant what is the antiderivative of

    f'(x) = (x^2-1)/x

    posted by Reen
  2. Write f(x) as
    f(x) = x - 1/x, and integrate it one term at a time.

    The integral (or "antiderivative", if you insist on using that term) of x is (x^2)/2. The integral of -1/x is -ln x. An arbitrary constant term can be added to the integral.

    posted by drwls

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