solve the linear equation
-10.8x + 1.4 = -47.6 - 1.0x
Use the discriminant to determine how many real-number solutions the equation has.
v^2 - 7v + 5 = 0
jessica, bring the x terms together and the simple numbers together, then you can just divide across:
-10.8x + 1.4 = -47.6 - 1.0x
-10.8x + 1.0x = -47.6 - 1.4
-9.8x = -49
x = -49/-9.8
Check my arithmetic, and finish from there.
chandice, it's better to post a new message when you have a new question.
Anyway, the discriminant of a quadratic is b^2-4ac, the bit inside the square root sign of the quadratic formula.
In this case:
b^2-4ac
=7^2-4*5
which is greater than zero. What does that tell you about the roots?
how many real-number solutions does the equation have?
To solve the linear equation -10.8x + 1.4 = -47.6 - 1.0x, we need to simplify and rearrange the equation to isolate the variable "x" on one side.
Step 1: Distribute the -1.0x to the terms on the right side:
-10.8x + 1.4 = -47.6 - 1.0x
-10.8x + 1.4 = -47.6 + (-1.0x)
-10.8x + 1.4 = -47.6 - 1.0x
Step 2: Combine like terms on the right side:
-10.8x + 1.4 = -47.6 - x
Step 3: Move all terms containing "x" to the left side and constant terms to the right side:
-10.8x + x = -47.6 - 1.4
-10.8x + x = -48.6
Step 4: Combine like terms on both sides of the equation:
-9.8x = -48.6
Step 5: To isolate the variable "x", divide both sides of the equation by -9.8:
x = -48.6 / -9.8
Step 6: Simplify the division:
x = 4.96
So, the solution to the linear equation is x = 4.96.