I have to find the vertex, axis of symmetry, and x intercepts of x^2-x+(5/4). I put it in standard form as -(x+-.5)^2+1.5. Thus, the vertex would be .5, 1.5. But the book's answer is 1/2, 1. How did they get this?

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asked by Erin
  1. You got the standard form wrong.

    x^2 - x + (5/4) = (x - 1/2)^2 + 1

    The minimum (vertex) is at x = 1/2, and the value of y there is 1.

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    posted by drwls
  2. Where did the 1 come from in the standard form come from? How did the 5/4 become 1 when it was transferred to outside of the parentheses?

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    posted by Erin

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