y=(x+3)(x-1)

What is the question? Do they want you to multiply it out? Or find out the x values for which y is zero?

You have only written an equation. Not a question.

The given equation is a quadratic equation in the form of y = (x + 3)(x - 1). To understand what this equation represents, we can start by expanding the equation:

y = (x + 3)(x - 1)
= x(x - 1) + 3(x - 1)
= x^2 - x + 3x - 3
= x^2 + 2x - 3

So, the equation y = (x + 3)(x - 1) is equivalent to y = x^2 + 2x - 3.

This quadratic equation represents a parabola on a graph. The coefficients of the equation give us information about the shape, position, and direction of the parabola.

For example:
- The coefficient of x^2 (which is 1 in this case) determines the shape of the parabola. If it is positive, the parabola opens upward, and if it is negative, the parabola opens downward.
- The coefficient of x (which is 2 in this case) gives us information about the direction and steepness of the parabola.
- The constant term (which is -3 in this case) gives us the y-intercept of the parabola, which is the point where it intersects the y-axis.

To graph this equation, you can follow these steps:
1. Determine the vertex of the parabola using the formula x = -b/2a. In this case, a = 1 and b = 2. So, x = -2/(2*1) = -1. This gives us the x-coordinate of the vertex.
2. Substitute the x-coordinate of the vertex (which is -1) into the equation to find the y-coordinate. In this case, y = (-1)^2 + 2(-1) - 3 = 1 - 2 - 3 = -4.
So, the vertex of the parabola is (-1, -4).
3. Plot the vertex on the graph.
4. Determine additional points by substituting different x-values into the equation and calculating the corresponding y-values.
5. Plot these points on the graph.
6. Draw a smooth curve passing through the plotted points to complete the graph of the parabola.

I hope this explanation helps you understand the given equation and how to graph it!