How will the volume of a fixed sample of gas change if its pressure is doubled and the Kelvin temperature is doubled?
a)the change cannot be determined without more specific information
b)it will decrease by a factor of 2
c)it will increase by a factor of 4
d)no change
e)it will double
**would it be d? since the pressure is doubled, the volume would be halved. and if the temperature is double it would double the halved volume, bringing it back to where it was in the beginning. Would that be right?
No, the correct answer is c) it will increase by a factor of 4. This is known as the combined gas law, which states that the volume of a fixed sample of gas is directly proportional to the ratio of its Kelvin temperature and pressure. When the pressure is doubled, the volume will be halved (as you correctly stated). And when the Kelvin temperature is doubled, the volume will also double. Therefore, the overall effect is an increase in volume by a factor of 4.
Yes, your reasoning is correct. The answer is d) no change.
To understand why, we can use the ideal gas law, which states that the product of pressure (P) and volume (V) is proportional to the product of the number of moles (n) and the Kelvin temperature (T):
PV = nRT
Where R is the ideal gas constant.
In this case, the number of moles and the gas constant remain constant, so we can simplify the equation to:
PV = constant
If we double the pressure (P) and double the Kelvin temperature (T), the equation becomes:
2P * 2T = constant
We can see that the product of the pressure and the temperature is still constant. Therefore, the volume (V) will also remain constant. Therefore, the correct answer is d) no change.
Yes, that's reasoning.
You may want to try it with the formula.
PV = nRT
Solve for V.
V = nRT/P
V = nR*2T/2P
The 2s cancel so the V is the same.