A 500.0-mL sodium iodide (NaI) solution was prepared by dissolving 37.7g of solid NaI in water. Chlorine gas was bubbled through a 100.0-mL sample of this solution until the reaction was complete. How many grams of molecular iodine were produced?
How many grams of I is in 37.7g NaI ?
I can figure out that 37.7g NaI = .252 mol NaI. I have no clue how to solve this one.. I don't want the answer I just need the steps to get to it
To determine the number of grams of molecular iodine (I2) produced, we need to understand the chemical reaction that occurs when chlorine gas (Cl2) reacts with sodium iodide (NaI). This reaction is represented by the following balanced chemical equation:
2NaI + Cl2 -> 2NaCl + I2
According to the equation, two moles of sodium iodide react with one mole of chlorine gas to produce two moles of sodium chloride and one mole of molecular iodine.
First, let's calculate the number of moles of sodium iodide in the 500.0-mL solution. We can use the formula:
moles = mass / molar mass
The molar mass of sodium iodide (NaI) is the sum of the atomic masses of sodium (Na) and iodine (I):
molar mass of Na = 22.99 g/mol
molar mass of I = 126.9 g/mol
molar mass of NaI = molar mass of Na + molar mass of I
The molar mass of NaI is:
molar mass of NaI = 22.99 g/mol + 126.9 g/mol = 149.89 g/mol
Now we can calculate the moles of sodium iodide:
moles of NaI = mass of NaI / molar mass of NaI
mass of NaI = 37.7g
moles of NaI = 37.7g / 149.89 g/mol
Next, let's determine the number of moles of molecular iodine produced. From the balanced chemical equation, we know that the mole ratio between sodium iodide and molecular iodine is 1:1. Therefore, the number of moles of iodine produced will be the same as the number of moles of sodium iodide:
moles of I2 = moles of NaI
Now, to calculate the grams of molecular iodine produced, we need to find the mass using the formula:
mass = moles of I2 * molar mass of I2
The molar mass of molecular iodine (I2) is the sum of the atomic masses of iodine (I):
molar mass of I2 = molar mass of I + molar mass of I
molar mass of I2 = 126.9 g/mol + 126.9 g/mol = 253.8 g/mol
Finally, we can calculate the grams of molecular iodine produced:
grams of I2 = moles of I2 * molar mass of I2
Therefore, plug in the moles of NaI calculated earlier:
grams of I2 = moles of NaI * molar mass of I2
Follow the steps to calculate the final result.