What is the Dividing Power of 12 a to the 2nd power or squared b to the 3rd power of cubed over or Divided by 6 a to the 2nd power b
Im not sure yet but Im working it out now
Do you mean
(12a^2b^3)/(6a^2b)
If so that would come out to
2b^2
(in this forum we write something like
"5 raised to the third" as 5^3)
Jibberish
To calculate the dividing power of the expression (12a^2b^3)^3 / (6a^2b), we can simplify the expression step by step.
First, let's deal with the numerator: (12a^2b^3)^3.
To raise a term to an exponent, we raise each component of the term to that exponent. Applying the exponent of 3:
(12^3) * (a^2)^3 * (b^3)^3
Simplifying further:
Then simplify each component separately:
(12^3) = 12 * 12 * 12 = 1728
(a^2)^3 = a^(2*3) = a^6
(b^3)^3 = b^(3*3) = b^9
Now, let's deal with the denominator: 6a^2b.
Multiplier 6 is already simplified, so we just need to consider the powers of a and b:
(a^2) stays the same.
(b) since it only has an exponent of 1, it stays the same.
Combining everything, the expression becomes:
(1728a^6b^9) / (6a^2b)
To divide, we can simply divide the corresponding components:
(1728/6) * (a^6/a^2) * (b^9/b)
Simplifying further:
288 * a^(6-2) * b^(9-1)
288 * a^4 * b^8
So, the dividing power of the expression (12a^2b^3)^3 / (6a^2b) is 288a^4b^8.