Write the answer to the problem as an algebraic expression.
A theater ticket for adults is “A” dollars and the price of a child's ticket is “C” dollars. If 29 adults and 35 children attend the theater one night, how much money did the theater collect?
Sorry, I just can get story problems...
How much would 29 adult tickets cost?
How much would 35 child's ticket cost?
Add up the two answers and voilà!
Don't worry, I can help you with understanding and solving the problem. Let's break it down step by step.
We know that the number of adults attending the theater is 29 and the number of children attending is 35. The cost of an adult ticket is "A" dollars, and the cost of a child ticket is "C" dollars.
To find out how much money the theater collected, we need to calculate the total value of all the adult tickets and all the child tickets.
The total value of adult tickets can be calculated by multiplying the number of adults (29) with the cost of each adult ticket (A):
Total value of adult tickets = Number of adults × Cost of each adult ticket = 29A
Similarly, the total value of child tickets can be calculated by multiplying the number of children (35) with the cost of each child ticket (C):
Total value of child tickets = Number of children × Cost of each child ticket = 35C
To find the total amount of money the theater collected, we need to add the total values of the adult and child tickets together:
Total money collected = Total value of adult tickets + Total value of child tickets = 29A + 35C
So, the algebraic expression representing the problem is 29A + 35C.