2.02g of KNO3 ( Mz=101) is dissolved in sufficient water to prepare 0,500 dm3 of solution. What is the concentration of this solution in mol dm?

Bob Pursley gave you the information in your previous post. M = moles/L.

So I would change 2.02 g KNO3 to moles and divide that by the volume in dm^3. Again, I must ask just what mol dm means?

To find the concentration of the solution in mol dm^3, we need to calculate the number of moles of KNO3 dissolved in the solution and then divide it by the volume of the solution.

Step 1: Calculate the number of moles of KNO3.
Given: Mass of KNO3 = 2.02 g
Molar mass of KNO3 = 101 g/mol

Number of moles = Mass / Molar mass
Number of moles = 2.02 g / 101 g/mol
Number of moles = 0.02 mol

Step 2: Calculate the concentration of the solution.
Given: Volume of the solution = 0.500 dm^3

Concentration = Number of moles / Volume
Concentration = 0.02 mol / 0.500 dm^3
Concentration = 0.04 mol dm^-3

Therefore, the concentration of the solution is 0.04 mol dm^-3.

To find the concentration of the solution in mol dm^-3, you need to know two pieces of information: the amount of solute (in moles) and the volume of the solution (in dm^3).

First, we need to calculate the number of moles of KNO3 (potassium nitrate) in the given mass (2.02 g). We can use the formula:

moles = mass / molar mass

The molar mass of KNO3 is calculated by adding the atomic masses of potassium (K), nitrogen (N), and oxygen (O). Given that the atomic mass of potassium (K) is 39.1 g/mol, nitrogen (N) is 14.0 g/mol, and oxygen (O) is 16.0 g/mol, we have:

molar mass of KNO3 = (39.1 + 14.0 + (16.0 * 3)) g/mol = 101 g/mol

Now, we can calculate the number of moles of KNO3:

moles = 2.02 g / 101 g/mol = 0.02 mol

Next, we need to determine the volume of the solution in dm^3, which is given as 0.500 dm^3.

Finally, we can calculate the concentration (C) of the solution using the formula:

C = moles / volume

Plugging in the values, we have:

C = 0.02 mol / 0.500 dm^3 = 0.04 mol dm^-3

Therefore, the concentration of the solution is 0.04 mol dm^-3.