Two dice are rolled. Find the odds that the score on the dice is either 10 or at most 5.

Since each die has 6 numbers, there are 36 possible combinations with two dice.

10 can only be obtained by 5 & 5, 6 & 4 or 4 & 6 = 3/36

"At most 5" = 5 or less, which can be obtained by 1 & 1, 2 & 2, 3 & 2, 2 & 3, 1 & 2, 2 & 1, 1 & 3, 3 & 1, 1 & 4 or 4 & 1 = 10/36

The probability of "either-or" events is obtained by adding the probability of the separate events.

the Odds in favor of getting 7

wo dice are rolled. Find the odds that the score on the dice is either or at most .

Ah, the fascinating world of dice rolling! Let's calculate the odds, shall we?

Let's break it down. We have two dice, each with six sides. To find the total number of possible outcomes, we multiply the number of sides on each die: 6 x 6 = 36.

Now, let's identify the possible outcomes that satisfy our condition. We have two cases to consider:

Case 1: The score on the dice is 10.
There are only two possible outcomes that give us a total score of 10: (4, 6) and (6, 4). So, 2 out of 36 outcomes satisfy this condition.

Case 2: The score on the dice is at most 5.
To find the number of outcomes satisfying this condition, we need to count the possibilities. Let's see:
1. (1, 1)
2. (1, 2)
3. (1, 3)
4. (1, 4)
5. (1, 5)
6. (2, 1)
7. (2, 2)
8. (2, 3)
9. (2, 4)
10. (3, 1)
11. (3, 2)
12. (3, 3)
13. (4, 1)
14. (4, 2)
15. (5, 1)

There are 15 outcomes out of 36 that satisfy this condition.

To find the total number of outcomes that satisfy either of the two conditions, we need to add up the results from each case:

Case 1: 2 outcomes
Case 2: 15 outcomes

Total outcomes satisfying either condition: 2 + 15 = 17

Therefore, the odds of rolling a score of either 10 or at most 5 are 17 to 36, or simplified 17/36.

And remember, if your luck doesn't quite roll your way, you can always resort to good old-fashioned clown humor!

To find the odds that the score on the two dice is either 10 or at most 5, we first need to determine the total number of possible outcomes when rolling two dice.

Each die has six sides and can show numbers from 1 to 6. When we roll two dice, the total number of possible outcomes is the product of the number of outcomes for each die, which is 6 x 6 = 36.

Now, let's calculate the number of favorable outcomes for the given conditions.

For a total score of 10, the possible combinations are:

- (4, 6)
- (5, 5)
- (6, 4)

So, there are 3 favorable outcomes for a total score of 10.

For a total score at most 5, the possible combinations are:

- (1, 1) - sum is 2
- (1, 2) - sum is 3
- (1, 3) - sum is 4
- (1, 4) - sum is 5
- (2, 1) - sum is 3
- (2, 2) - sum is 4
- (2, 3) - sum is 5
- (3, 1) - sum is 4
- (3, 2) - sum is 5
- (4, 1) - sum is 5

So, there are 10 favorable outcomes for a total score at most 5.

Therefore, the total number of favorable outcomes is 3 + 10 = 13.

Finally, to find the odds, we need to divide the number of favorable outcomes by the total number of possible outcomes. So, the odds are 13/36.