What is the probability of rolling a number that is divisible by 2 or 3?
What is rolling a number?
you can roll 2,3,4,6
so, four numbers out of a possible six
Pr=4/6
This is refering to rolling a single die...so the probability would be 1 out of 6, right?
No. You can roll any of four numbers out of six possibilities.
That is right, because 4 and 6 are divisible by 2 and 3. I was just thinking of 2 and 3. Thanks again.
Rolling a number typically refers to rolling a standard six-sided die and obtaining a number. In this case, we are considering a fair six-sided die, which means every number from 1 to 6 has an equal chance of being rolled.
To find the probability of rolling a number that is divisible by 2 or 3, we need to determine the favorable outcomes (the numbers that meet the given condition) and divide it by the total number of possible outcomes.
Let's start by listing the numbers that are divisible by 2: 2, 4, and 6.
Now, let's list the numbers that are divisible by 3: 3 and 6.
To find the numbers that are divisible by 2 or 3, we combine these lists: 2, 3, 4, and 6.
So, there are four favorable outcomes: 2, 3, 4, and 6.
Since a six-sided die has a total of six possible outcomes (numbers 1 to 6), the probability can be calculated as:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
= 4 / 6
= 2 / 3
Therefore, the probability of rolling a number that is divisible by 2 or 3 is 2/3, which can also be expressed as approximately 0.67 or 67%.