a snowball rolls off the edge of a horizontal roof at a velocity of 7 m/s. what is the speed of the snowball 3 s later?
vertical speed=g*t=9.8*3
horizontal speed=7m/s
speed= sqrt (7^2+29.6^2)
To find the speed of the snowball 3 seconds later, we need to consider the effect of gravity on the snowball's motion.
Here's how we can solve it step by step:
Step 1: Identify the initial velocity.
The initial velocity of the snowball rolling off the roof is given as 7 m/s.
Step 2: Determine the acceleration due to gravity.
The acceleration due to gravity on Earth is approximately 9.8 m/s². Since the snowball is falling freely under gravity, its acceleration will be equal to 9.8 m/s² downward.
Step 3: Calculate the final velocity after 3 seconds.
We can use the following equation of motion:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Plugging in the given values:
u = 7 m/s (initial velocity)
a = 9.8 m/s² (acceleration due to gravity)
t = 3 s (time)
v = 7 m/s + (9.8 m/s²)(3 s)
v = 7 m/s + 29.4 m/s
v = 36.4 m/s
Therefore, the speed of the snowball 3 seconds later is 36.4 m/s.
To determine the speed of the snowball 3 seconds later, we need to know if any external forces are acting on the snowball. However, assuming no significant external forces, we can use the principle of conservation of energy.
The snowball's initial velocity is 7 m/s. Due to the absence of any significant external forces, the only force acting on the snowball is gravity. As the snowball rolls off the edge of the roof, it will only be under the influence of gravity.
Using the equation of motion:
v = u + gt
where:
v = final velocity
u = initial velocity
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
Applying the values to the equation:
v = 7 + (9.8 * 3)
v = 7 + 29.4
v = 36.4 m/s
Therefore, the speed of the snowball 3 seconds later is approximately 36.4 m/s.