3 over the square root of 6
3/sqrt6= sqrt3*sqrt3/(sqrt2*sqrt3)
= sqrt3/sqrt2=sqrt3*sqrt2/sqrt2*sqrt2
= 1/2 sqrt6
its supposed to be
I THINK IT I SUPPSOED TO BE 1.2
To compute the value of 3 divided by the square root of 6, we can follow these steps:
Step 1: Simplify the expression.
To start, we simplify the denominator, which is the square root of 6. The square root of 6 cannot be simplified further, so we leave it as it is.
Step 2: Rationalize the denominator.
Rationalizing the denominator means eliminating any square roots from the denominator.
To do this, multiply both the numerator and denominator by the conjugate of the denominator. The conjugate of the square root of 6 is the negation of the square root of 6: (-√6).
So, we multiply the expression by (-√6)/(√6):
(3/√6) * (-√6)/(√6)
This gives us:
-3√6 / (√6 * √6)
= -3√6 / 6
= -√6 / 2
Thus, the value of 3 over the square root of 6 is equal to -√6 / 2.